Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.2 Exponential Functions - 4.2 Exercises - Page 431: 46

Answer

domain $(-\infty,\infty)$, range $(-\infty,0)$ See graph.

Work Step by Step

To graph function $f(x)=-2^{-x}=-(\frac{1}{2})^x$, start from $y=2^x$, reflect across the y-axis, then reflect across the x-axis. For $f(x)$, we have domain $(-\infty,\infty)$, range $(-\infty,0)$ See graph.
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