Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.1 Inverse Functions - 4.1 Exercises - Page 418: 92

Answer

$2$

Work Step by Step

Given $f(2)=3$, we have $f^{-1}(3)=2$ and $(f^{-1}\circ f)(2)=f^{-1}(f(2))=f^{-1}(3)=2$
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