Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - Test - Page 404: 17

Answer

(a) $270.08$ (b) See figure, increases $(0,5.9)\cup(9.5,15)$, decreases $(5.9,9.5)$

Work Step by Step

Given $f(t)= 1.06t^3 - 24.6t^2 + 180t$, we have: (a) for $t=2$, $ƒ(2)= 1.06(2)^3 - 24.6(2)^2 + 180(2)=270.08$ (b) Graph the function as shown in the figure, we can find that the function increases over $(0,5.9)\cup(9.5,15)$ and decreases over $(5.9,9.5)$
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