Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - Test - Page 403: 9

Answer

See explanations.

Work Step by Step

Step 1. Use Descartes's Rule, since $f(x)$ has no sign change, there is no real positive zeros. Step 2. Since $f(-x)=f(x)$ and there is no sign change in $f(-x)$, there is no real negative zeros. Step 3. We conclude that the function has no real zeros.
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