Answer
Yes, $6^3+7x^2-14x-8$.
Work Step by Step
Let $f(x)=6x^4-11x^3-35x^2+34x+24$, use synthetic division as shown in the figure, we have $\frac{f(x)}{x-3}=6^3+7x^2-14x-8$. Thus $x-3$ is a factor of $f(x)$ and the other factor is $6^3+7x^2-14x-8$.
