Answer
$(-\sqrt 3, -\frac{1}{2})\cup(\frac{1}{2},\sqrt 3)$
Work Step by Step
Given $-4x^4+13x^2-3\gt0$, we can identify it as an inequality. Graph $f(x)=-4x^4+13x^2-3$ as shown in the figure and we can find the solution set as $(-\sqrt 3, -\frac{1}{2})\cup(\frac{1}{2},\sqrt 3)$
