Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - Chapter 3 Test Prep - Review Exercises - Page 402: 90

Answer

$\frac{1}{2}$.

Work Step by Step

Step 1. As z varies inversely as w, we have $z=\frac{k}{w}$ where $k$ is a constant. Step 2. As $z=10$ when $w=\frac{1}{2}$, we have $10=\frac{k}{1/2}$, thus $k=5$ Step 3. For $w=10$, we have $z=\frac{5}{10}=\frac{1}{2}$.
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