Answer
1 real positive zero.
2 or 0 real negative zeros.
see table.
Work Step by Step
Step 1. Given $f(x)=x^3+3x^2-4x-2$, there is 1 sign change indicating 1 real positive zero.
Step 2. $f(-x)=-x^3+3x^2+4x-2$, there are 2 sign changes indicating 2 or 0 real negative zeros.
Step 3. The total number of zeros is 3, thus nonreal complex zeros can be calculated as shown in the table.
