Answer
$\{-1, \frac{1}{2}, 5\}$
Work Step by Step
Step 1. List possible rational zeros as $\frac{p}{q}=\pm1,\pm5,\pm\frac{1}{2},\pm\frac{5}{2}$
Step 2. Use synthetic division to find one zero at $x=-1$ as shown in the figure.
Step 3. Use the quotient to find the other zeros: $2x^2-11x+5=0$ or $(x-5)(2x-1)=0$, thus $x=\frac{1}{2}, 5$
Step 4. The solution set is $\{-1, \frac{1}{2}, 5\}$
