Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - Chapter 3 Test Prep - Review Exercises - Page 399: 33

Answer

$f(x) =x^4-5x^3+3x^2+15x-18$

Work Step by Step

Given zeros at $x=\pm\sqrt 3,2,3$, we can write a possible form of the function as $f(x)=(x-\sqrt 3)(x+\sqrt 3)(x-2)(x-3)=x^4-5x^3+3x^2+15x-18$
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