Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - 3.6 Variation - 3.6 Exercises - Page 391: 58

Answer

$324$ times of its original value.

Work Step by Step

Step 1. Based on the given conditions, we have $m=kp^2q^4$ where $k$ is a constant. Step 2. If $p'=2p, q'=3q$, we have $m'=k(2p)^2(3q)^4=324m$ Step 3. Thus, $m$ will be $324$ times of its original value.
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