Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - 3.6 Variation - 3.6 Exercises - Page 387: 16

Answer

$y=45/16$

Work Step by Step

"y vary directly as x, and inversely as $m^2$ and $r^2$" can be written as: $y=\frac{kx}{m^2r^2}$ With the information regarding the value of y, x, m and r, we are able to find constant k. $\frac{5}{3}=\frac{k}{2^2*3^2}$ $3k=5*4*9=180$ $k=60$ Then, we can use this k constant and the information of another set of x, m and r to find y. $y=\frac{60*3}{1^2*8^2}=\frac{180}{64}=45/16$
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