Answer
$f(x)=\frac{(x-1)(x-3)}{x(x-2)}$
Work Step by Step
Step 1. From the given conditions, we have: $f(1)=f(3)=0$, V.A. $x=0,2$, H.A. $y=1$,
Step 2. Thus, a possible rational function can be written as $f(x)=\frac{(x-1)(x-3)}{x(x-2)}$
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