Answer
$f(x)=\frac{-(x+1)(x-2)}{(x+3)(x-3)}$
Work Step by Step
Step 1. From the given graph, we can identify: V.A. $x=\pm3$, H.A. $y=-1$, $f(-1)=f(2)=0$
Step 2. Thus, a possible rational function can be written as $f(x)=\frac{-(x+1)(x-2)}{(x+3)(x-3)}$