Answer
$V.A.$ $x=-2$ and $x=\frac{5}{2}$,
$H.A$ $y=\frac{1}{2}$,
$O.A.$ $none$.
Work Step by Step
Given $f(x)=\frac{x^2-2x-3}{2x^2-x-10}=\frac{(x+1)(x-3)}{(x+2)(2x-5)}$, we can identify the following:
vertical asymptote $V.A.$ $x=-2$ and $x=\frac{5}{2}$,
horizontal asymptote $H.A$ $y=\frac{1}{2}$,
oblique asymptote $O.A.$ $none$.