Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - 3.5 Rational Functions: Graphs, Applications, and Models - 3.5 Exercises - Page 375: 33

Answer

$E$.

Work Step by Step

Since $f(x)=\frac{x^2-16}{x+4}=\frac{(x+4)(x-4)}{x+4}=x-4\ (x\ne-4)$ has a hole at $(-4,-8)$, the choice is $E$.
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