Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - 3.4 Polynomial Functions: Graphs, Applications, and Models - 3.4 Exercises - Page 352: 56

Answer

See explanations.

Work Step by Step

Step 1. Given $f(x)=x^5+2x^4+x^3+3$, for $x=-1.8$, we have $f(-1.8)=(-1.8)^5+2(-1.8)^4+(-1.8)^3+3=-0.73248\lt0$ Step 2. For $x=-1.7$, we have $f(-1.7)=(-1.7)^5+2(-1.7)^4+(-1.7)^3+3=0.59263\gt0$ Step 3. As $f(-1.8)$ and $f(-1.7)$ have opposite signs, based on the intermediate value theorem, there is a real zero between -1.8 and -1.7.
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