Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - 3.3 Zeros of Polynomial Functions - 3.3 Exercises - Page 336: 27

Answer

$f(x)=(x-3i)(x+3)(x+4)$

Work Step by Step

Step 1. Use the given coefficients of the polynomial to set up a division as shown in the figure. Step 2. Perform a synthetic division and find the quotient as $x^2+7x+12$. Step 3. Factor $x^2+7x+12$ to get $(x+3)(x+4)$ thus $f(x)=(x-3i)(x+3)(x+4)$
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