Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Test - Page 301: 7

Answer

(a) $x^2+y^2=4$ (b) $(x-1)^2+(y-4)^2=1$

Work Step by Step

(a) We can identify the center as $(0,0)$ and radius as $2$, thus the equation is $x^2+y^2=4$ (b) We can identify the center as $(1,4)$ and radius as $1$, thus the equation is $(x-1)^2+(y-4)^2=1$
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