Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Test - Page 301: 3

Answer

$\sqrt {34}$

Work Step by Step

Use the distance formula, we have the distance between the two points as $d=\sqrt {(3-(-2))^2+(4-1)^2}=\sqrt {25+9}=\sqrt {34}$
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