Answer
(a) domain $[-7,3]$, range $[-5,5]$.
(b) not a function.
Work Step by Step
(a) Given $(x+2)^2+y^2=25$, we can identify it as a circle with center at $(-2,0)$ and radius $5$, and we can find its domain as $[-7,3]$, range as $[-5,5]$.
(b) We can rewrite the equation as $y^2=25-(x+2)^2$ and $y=\pm\sqrt {25-(x+2)^2}$ which does not represent a function.