Answer
(a) $y=\frac{5}{8}x+5$
(b) $5x-8y=-40$
Work Step by Step
(a) A line perpendicular to $8x+5y=3$ with slope $-\frac{8}{5}$ will have a slope $m=\frac{5}{8}$. Together with point $(0,5)$, we have $y-(5)=\frac{5}{8}x$ or $y=\frac{5}{8}x+5$
(b) Form standard form, we have $8y=5x+40$ which gives $5x-8y=-40$
