Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Chapter 2 Test Prep - Review Exercises - Page 297: 36

Answer

$f(0)=-2k^2+3k-6$

Work Step by Step

To find $f(k)$, substitute $k$ to $x$ in $f(x)$ to obtain: $f(x) =-2x^2+3x-6 \\f(0)=-2k^2+3k-6$
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