Answer
(a) $1-x^2-2xh-h^2$
(b) $-2xh-h^2$
(c) $-2x-h$
Work Step by Step
(a) Given $f(x)=1-x^2$, we have $f(x+h)=1-(x+h)^2=1-x^2-2xh-h^2$
(b) $f(x+h)-f(x)=1-(x+h)^2-1+x^2=-2xh-h^2$
(c) $\frac{f(x+h)-f(x)}{h}=-2x-h$
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