Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.8 Function Operations and Composition - 2.8 Exercises - Page 289: 53

Answer

(a) $1-x^2-2xh-h^2$ (b) $-2xh-h^2$ (c) $-2x-h$

Work Step by Step

(a) Given $f(x)=1-x^2$, we have $f(x+h)=1-(x+h)^2=1-x^2-2xh-h^2$ (b) $f(x+h)-f(x)=1-(x+h)^2-1+x^2=-2xh-h^2$ (c) $\frac{f(x+h)-f(x)}{h}=-2x-h$
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