Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.8 Function Operations and Composition - 2.8 Exercises - Page 287: 33

Answer

$\color{blue}{\bf{ (a) 2 } }$ $\color{blue}{\bf{ (b) 4 } }$ $\color{blue}{\bf{ (c) 0 } }$ $\color{blue}{\bf{ (d) - \dfrac{1}{3} } }$

Work Step by Step

$\bf{(a)}$We are given a graph and asked to find: $(f+g)(2)$ $f(2)+g(2)$ From the given graph we see that: $y=f(2)= 4$ and $y=g(2)= -2$ $4-2$ $\color{blue}{\bf{ 2 } }$ $\bf{( b )}$We are asked to find: $( f-g )( 1 )$ $f(1)-g(1)$ From the given graph we see that: $y= f(1) = 1 $ and $ y= g(1) = -3 $ $1-(-3)$ $1+3$ $\color{blue}{\bf{ 4 } }$ $\bf{( c )}$We are asked to find: $( fg )( 0 )$ From the given graph we see that: $y= f(0) = 0 $ and $y= g(0) = -4 $ $(0)(-4)$ $\color{blue}{\bf{ 0 } }$ $\bf{( d )}$We are asked to find: $( \dfrac{f}{g} )( 1 )$ From the given graph we see that: $y= f(1) = 1 $ and $y= g(1) = -3 $ $\dfrac{1}{-3}$ $\color{blue}{\bf{ - \dfrac{1}{3} } }$
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