Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.8 Function Operations and Composition - 2.8 Exercises - Page 286: 4

Answer

$$\color{blue}{\bf{ \frac{3}{4} }}$$

Work Step by Step

We are given the two functions $\bf{f}$ and $\bf{g}$ $\bf{f(x) = x + 1}$ and $\bf{g(x) = x^2}$ and asked to find $( \frac{f}{g} )(2)$ $( \frac{f}{g} )(2)=( \frac{f(2)}{g(2)} )$ $ \frac{2+1}{2^2}$ $ \frac{3}{4}$ $$\color{blue}{\bf{ \frac{3}{4} }}$$
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