Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.8 Function Operations and Composition - 2.8 Exercises - Page 286: 15

Answer

$$\color{blue}{\bf{ -38 }}$$

Work Step by Step

We are given the two functions $\bf{f}$ and $\bf{g}$ $\bf{f(x) = x^2 + 3}$ and $\bf{g(x) = -2x + 6}$ and asked to find $\bf{( fg )( 4 )}=f(4)\times{g(4)}$ $(4^2 + 3)( -2(4) + 6)$ $(16 + 3)( -8 + 6)$ $(19)( -2)$ $-38$ $$\color{blue}{\bf{ -38 }}$$
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