Answer
$$\color{blue}{\bf{ 12 }}$$
Work Step by Step
We are given the two functions $\bf{f}$ and $\bf{g}$
$\bf{f(x) = x^2 + 3}$ and $\bf{g(x) = -2x + 6}$
and asked to find $\bf{( ƒ + g)( 3)}$
$(ƒ + g)( 3)= f(3)+g(3)$
$(3^2 + 3)+(-2(3) + 6)$
$9 + 3-6 + 6$
$12$
$$\color{blue}{\bf{ 12 }}$$
