Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.6 Graphs of Basic Functions - 2.6 Exercises - Page 258: 50

Answer

See graph.

Work Step by Step

Step 1. It takes $\frac{20}{40}=0.5\ hr$ to the park, thus during $0\le x \le 0.5$, we have $f(x)=40x$ where $x$ is the time in hour, $f(x)$ is the distance from home. Step 2. Remain at the park for 2 hrs means $f(x)=20$ for $0.5\lt x \le 2.5$ Step 3. It takes $\frac{20}{20}=1\ hr$ back from the park, thus during $2.5\lt x \le 3.5$, we have $f(x)=20-20(x-2.5)$ Step 4. Combine the above results, we have $f(x)=\begin{cases} 40x,\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0\le x \le 0.5\\ 20,\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.5\lt x \le 2.5 \\ 20-20(x-2.5),\ 2.5\lt x \le 3.5 \end{cases}$ Step 5. We can graph the above function as shown in the figure.
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