Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.6 Graphs of Basic Functions - 2.6 Exercises - Page 257: 42

Answer

$f(x)=\begin{cases} 2x-3,\ x\lt 2 \\3,\ \ \ \ \ \ \ \ \ \ x=2 \\ 2x-3,\ x\gt 2\end{cases}$ domain $(-\infty,\infty)$ and range $(-\infty,1)U\{ 3\}U(1,\infty)$

Work Step by Step

Step 1. Identify the left line equation as $y=2x-3$ with $x\lt 2$. Step 2. Identify the right line equation as $y=2x-3$ with $x\gt 2$. Step 3. Identify the middle point as $y=3$ with $x=2$. Step 4. Combine the above to get: $f(x)=\begin{cases} 2x-3,\ x\lt 2 \\3,\ \ \ \ \ \ \ \ \ \ x=2 \\ 2x-3,\ x\gt 2\end{cases}$ Step 5. Identify the domain as $(-\infty,\infty)$ and range as $(-\infty,1)U\{ 3\}U(1,\infty)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.