Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.4 Linear Functions - 2.4 Exercises - Page 231: 74

Answer

$-0.099$

Work Step by Step

Step 1. Identify the needed data: $x_1=2006, f(x_1)=4.53$ and $x_2=2014, f(x_2)=3.74$ Step 2. Use the formula for the average rate of change: $m=\frac{f(x_2)-f(x_1)}{x_2-x_1}$, we have $m=\frac{3.74-4.53}{2014-2006}\approx-0.099$
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