Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.3 Functions - 2.3 Exercises: 26

Answer

The given relation defines a function. domain: $\left\{2011, 2012, 2013, 2014\right\}$ range: $\left\{11,159,999, \space \space 11,210,832, \space \space 11,339,285, \space \space 11,181,735 \right\}$

Work Step by Step

RECALL: A function is a relation whose every first coordinate is paired with only one second coordinate. In the given relation, every first coordinate $(x)$ is paired with only one second coordinate $(y)$. Thus, the given relation defines a function. The domain is the set of values of $x$ so the domain is: $\left\{2011, 2012, 2013, 2014\right\}$ The range is the set of values of $y$ so the range is: $\left\{11,159,999, \space \space 11,210,832, \space \space 11,339,285, \space \space 11,181,735 \right\}$
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