Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.2 Circles - 2.2 Exercises - Page 202: 56

Answer

$3\sqrt 5$

Work Step by Step

The distance between $(-1,3)$ and $(5,-9)$ can be found as $2r=\sqrt {(-1-(5))^2+(3-(-9))^2}=\sqrt {180}=6\sqrt 5$, thus $r=3\sqrt 5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.