Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.2 Circles - 2.2 Exercises - Page 202: 55

Answer

$3\sqrt 5$

Work Step by Step

The distance between the center $(2,-3)$ and the point $(5,-9)$ can be found as $r=\sqrt {(2-(5))^2+(-3-(-9))^2}=\sqrt {45}=3\sqrt 5$
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