Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.2 Circles - 2.2 Exercises - Page 202: 53

Answer

$(2,-3)$

Work Step by Step

Given the endpoints $(-1,3)$ and $(5, -9)$ of a diameter, we can find its midpoint as $(\frac{-1+5}{2},\frac{3-9}{2})$ or $(2,-3)$
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