Answer
$(0, 5)$
Work Step by Step
RECALL:
The circle $(x-h)^2+(y-k)^2=r^2$ has its center at $(h, k)$ and a radius of $r$ units.
The given equation can be written as:
$(x-0)^2+(y-5)^2=3^2$
Thus, the center of the circle is at $(0, 5)$.
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 2 - Graphs and Functions - 2.2 Circles - 2.2 Exercises - Page 199: 4
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