Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.2 Circles - 2.2 Exercises: 4

Answer

$(0, 5)$

Work Step by Step

RECALL: The circle $(x-h)^2+(y-k)^2=r^2$ has its center at $(h, k)$ and a radius of $r$ units. The given equation can be written as: $(x-0)^2+(y-5)^2=3^2$ Thus, the center of the circle is at $(0, 5)$.
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