Answer
$\dfrac {3}{4}$
Work Step by Step
$\sum ^{\infty }_{i=1}\left( \dfrac {3}{7}\right) ^{i}=\dfrac {a_{1}}{1-r};a_{1}=\left( \dfrac {3}{7}\right) ^{1}=\dfrac {3}{7};r=\dfrac {3}{7}\Rightarrow S_{\infty }=\dfrac {\dfrac {3}{7}}{1-\dfrac {3}{7}}=\dfrac {3}{4}$