Answer
$\dfrac {8}{3}$
Work Step by Step
$r=\dfrac {\dfrac {1}{3}}{\dfrac {2}{3}}=\dfrac {\dfrac {2}{3}}{\dfrac {4}{3}}=\dfrac {1}{2}\Rightarrow S_{\infty }=\dfrac {a_{1}}{1-r}=\dfrac {\dfrac {4}{3}}{1-\dfrac {1}{2}}=\dfrac {8}{3}$
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