Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.2 Arithmetic Sequences and Series - 11.2 Exercises - Page 1026: 75

Answer

10100

Work Step by Step

$\sum ^{100}_{k=1}2k=\dfrac {a_{1}+a_{10}}{2}\times 100\Rightarrow a_{1}=2\times 1=2;a_{n_{0}}=2\times 100=200\Rightarrow S=\dfrac {2+200}{2}\times 100=10100$
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