Answer
$-500500$
Work Step by Step
$\sum ^{1000}_{i=1}-i=\dfrac {a_{1}+a_{1000}}{2}\times n=\dfrac {-1+\left( -1000\right) }{2}\times 1000=-500500$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 11 - Further Topics in Algebra - 11.2 Arithmetic Sequences and Series - 11.2 Exercises - Page 1026: 74
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