Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.2 Arithmetic Sequences and Series - 11.2 Exercises - Page 1025: 46

Answer

90

Work Step by Step

$S_{n}=\dfrac {2a_{1}+\left( n-1\right) d}{2}\times n;d=\left( -1\right) -\left( -5\right) =\left( -5\right) -\left( -9\right) =4\Rightarrow S_{10}=\dfrac {2\times \left( -9\right) +\left( 10-1\right) \times 4}{2}\times 10=90$
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