Answer
$(-\infty,-6]\cup[5,\infty)$
Work Step by Step
Step 1. Rewrite the inequality as $|2x+1|\geq11$
Step 2. Remove the absolute sign to get two cases: $2x+1\geq11$ and $2x+1\leq-11$
Step 3. For $2x+1\geq11$, we have $2x\geq10$ and $x\geq5$ or $[5,\infty)$
Step 4. For $2x+1\leq-11$, we have $2x\leq-12$ and $x\leq-6$ or $(-\infty,-6]$
Step 5. The solution set is $(-\infty,-6]\cup[5,\infty)$
