Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Test - Page 181: 15

Answer

$\frac{S-2LH}{2(H+L)}$

Work Step by Step

Start from the given formula, we have $S=2HW+2LW+2LH \longrightarrow S-2LH=2W(H+L) \longrightarrow \frac{S-2LH}{2(H+L)}=W$ thus, we have $W=\frac{S-2LH}{2(H+L)}$
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