Answer
$x=4$
Work Step by Step
Cube both sides to obtain:
$$(\sqrt[3]{2x+1})^3=(\sqrt[3]{9})^3
\\2x+1=9$$
Subtract $1$ to both sides:
$$2x+1-1=9-1
\\2x=8$$
Divide $2$ to both sides:
$$\dfrac{2x}{2}=\dfrac{8}{2}
\\x=4$$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 1 - Equations and Inequalities - Summary Exercises on Solving Equations - Exercises - Page 149: 15
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