Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises: 29

Answer

$=1-2i$

Work Step by Step

$\dfrac {-12-i}{-2-5i}=\dfrac {12+i}{2+5i}=\dfrac {\left( 12+i\right) \left( 2-5i\right) }{\left( 2+5i\right) \left( 2-5i\right) }=\dfrac {24-60i+2i-5i^{2}}{4-25i^{2}}=\dfrac {24-58i-5\times \left( -1\right) }{4-25\times \left( -1\right) }=\dfrac {29-58i}{29}=1-2i$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.