Answer
$\{ \frac{1\pm i\sqrt {23}}{2}\}$
Work Step by Step
For $x^2-x=-6$, we have $x^2-x+6=0$ which gives $x=\frac{1\pm\sqrt {1-4(6)}}{2}=\frac{1\pm i\sqrt {23}}{2}$ or in set form $\{ \frac{1\pm i\sqrt {23}}{2}\}$
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