Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.8 Absolute Value Equations and Inequalities - 1.8 Exercises - Page 169: 85

Answer

$\{ \frac{1\pm i\sqrt {23}}{2}\}$

Work Step by Step

For $x^2-x=-6$, we have $x^2-x+6=0$ which gives $x=\frac{1\pm\sqrt {1-4(6)}}{2}=\frac{1\pm i\sqrt {23}}{2}$ or in set form $\{ \frac{1\pm i\sqrt {23}}{2}\}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.