Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.8 Absolute Value Equations and Inequalities - 1.8 Exercises - Page 169: 83

Answer

$\pm6$

Work Step by Step

From $|x^2-x|=6$, we can remove the absolute value sign and obtain two cases: $x^2-x=6$ and $x^2-x=-6$. The two possible values are $\pm6$
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