Answer
$\{-6,-2,\frac{4}{3} \}$
Work Step by Step
Given the equation $(3x-4)(x+2)(x+6)=0$, use the zero-factor property, the solutions satisfy $3x-4=0$ or $x+2=0$ or $x+6=0$. Thus we have a solution set of $\{-6,-2,\frac{4}{3} \}$
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