Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.6 Other Types of Equations and Applications - 1.6 Exercises - Page 149: 112

Answer

$\{ 16\}$

Work Step by Step

Step 1. Rewrite the equation as $\sqrt x=x-12$ Step 2. Take square on both sides to get $x=x^2-24x+144$ or $x^2-25x+144=0$ Step 3. Factor and solve the equation: $(x-9)(x-16)=0$, thus $x=9, 16$ Step 4. Check answers in the original equation, only $\{ 16\}$ fits.
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