Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.6 Other Types of Equations and Applications - 1.6 Exercises - Page 149: 105

Answer

$h=\frac{d^2}{k^2}$

Work Step by Step

Step 1. Given $d=k\sqrt h$, we have $\sqrt h=\frac{d}{k}$ Step 2. Take square on both sides, we have $h=(\frac{d}{k})^2=\frac{d^2}{k^2}$
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